Acar drives horizontally off a 73-m-high cliff at a speed of 27 m/s. ignore air resistance. how long will it take the car to hit the ground?

At the edge of the cliff, the speed of the car will have two components. The x-component, horizontal, is equal to 27 m/s while the y-component, vertical, is equal to zero. With this, the car is seemingly in free-fall.

 The equation that would allow us to answer the question above is,

    d = (V₀)t + 0.5gt²

where d is distance, V₀ is the initial velocity, g is the acceleration due to gravity and t is the time. Substituting the known values,

    73 = (0)(t) + 0.5(9.8 m/s²)(t²)

Vo  equals zero because we only consider the y-component of the vector. Solving for the value of t will give us an answer of 3.86 s.

3.86 seconds

probably not if net force is zero