How much energy do individual photons of 450 nm light have?

The energy of individual photons of 450 nm light is 4.42 × 10⁻¹⁹ Joule

Further explanation

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

E = Energi of A Photon ( Joule )

m = Mass of an Electron ( kg )

v = Electron Release Speed ( m/s )

Ф = Work Function of Metal ( Joule )

q = Charge of an Electron ( Coulomb )

V = Stopping Potential ( Volt )

Let us now tackle the problem!

Given:

λ = 450 nm = 450 × 10⁻⁹ m

Unknown:

E = ?

Solution:

Learn morePhotoelectric Effect : linkStatements about the Photoelectric Effect : linkRutherford model and Photoelecric Effect : linkPhotoelectric Threshold Wavelength : linkAnswer details

Grade: High School

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt

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