Asmall rocket is launched vertically, attaining a maximum speed at burnout of 1.0 ✕ 10^2 m/s and thereafter coasting straight up to a maximum altitude of 1494 m. assuming the rocket accelerated uniformly while the engine was on, how long did it fire and how high was it at engine cut off

The distance traveled and time taken by the rocket  are 1488.89 m and 14.8 sec.

Explanation:

Given that,

Initial velocity

Altitude = 1494 m

We need to calculate the distance

Using equation of motion

Where, v = final velocity

u = initial velocity

a = acceleration due to gravity

s = distance

Put the value into the formula

So, The distance from the start of the coast to the end is 5.10204 m

The distance traveled by the rocket

We need to calculate the time

Using formula of time

Where, v = speed

t = time

d = distance

Put the value into the formula

Hence, The distance traveled and time taken by the rocket  are 1488.89 m and 14.8 sec.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =