A variable resistor is set to a value of 5 ohms, and a current-voltage (I-V) graph (with I on the y-axis and V on the x-axis) is plotted for it. Its resistance is then doubled to 10 ohms. What effect will this have on its I-V graph?

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

the maxium height is 34m/s