Physics, 19.02.2022 23:40, Tymere2011

An electron in a magnetic field moves along a circle with a radius of 40.4 m with a speed that follows: v(t) = v0 e^-bt
where b = 0.73 s^-1 and v0= 445 m/s.
What is the angular acceleration at t= 3s?

Answers: 2

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An electron in a magnetic field moves along a circle with a radius of 40.4 m with a speed that follows: v(t) = v0 e^-bt where b = 0.73 s^-1 and v0= 445 m/s. What is the angular acceleration at t= 3s?

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An electron in a magnetic field moves along a circle with a radius of 40.4 m with a speed that follows: v(t) = v0 e^-bt
where b = 0.73 s^-1 and v0= 445 m/s.
What is the angular acceleration at t= 3s?