A dragster car accelerates from a stopped position at a constant rate. It can travel the distance of a quarter of a mile (400m) in 7.68 seconds. What is its velocity as it crosses the finish line?

The magnets would be | n s | and | s n|

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Answer the radiant sun;

Physical science b final exam bernoulli’smovepowercompound translucent the sun i was having such a pain for this searching every question so i hope i made someone happy