Calculate the pressure of the water at the bottom of the pool.(b) The density of the water in a swimming pool is 1000kg/m°. The pool is 3m deep.

the answer is 46 mls because when you add the speed per second it increses the speed

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft