a 5.0 kg object is moved at 16m/s when a 2 N force is applied opposite to the direction of the objects motion causing it to slow down to 12 m/a. How long was this force applied?

And we need to find out the time during which the force was applied. As we know that the rate of change of momentum is directly proportional to the applied force in the dirⁿ of the force , where the value of constant is 1. So ,

F = ∆p/t

F = m (v - u)/t

-2N = 5kg ( 12-16)/t

t = -2 * -4 /5 s

t = 8/5 s

t = 1.6 s

i guess it’s a and b

the ima (higher than 1m) will be greater than the ima with the height of 1m.