The two pendulums shown in the figure below, each consist of a uniform solid ball of mass M supported by a rigid massless rod, but the ball for pendulum A is very tiny while the ball for pendulum B is much larger having a non-negligible radius R = 1.15 m. The length L in the figure is L = 1.6 m. Find the ratio of the ratio TB/TA of the period of pendulum B to the period of pendulum A.

P = 2 pi (I0 / M g L)^1/2 for object with inertia of I0

Note that if I0 = M L^2 you have P = 2 pi (L / g)^1/2 the simple pendulum

Radius of sphere = 1.15 = .719 L

I0 = M L^2 + 2/5 M (.719 L)^2 = 1.207 M L^2

P2 = 2 pi (1.207 M L^2 / M g L)^1/2 = 2 pi (1.207 L / g)^1/2

P2 / P1 = (1.207 / 1)^1/2 = 1.10     ratio of periods

i guess it’s a and b

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.