An electric kettle has a power rating of 2.4kW. How long does it take the kettle to heat up 4.5kg of tap water from 28°C to 100°C ? (c of water = 4200Jkg1°C-) What assumption must you make to arrive the answer ? pls helppp

Assumption :

- The process is adiabatic

- Heat from electric kettle is constant

- Efficiency of electric kettle is 100%

Q = m • c • ∆T

P • t = m • c • ∆T

2400t= (4.5 kg)(4200 J/kg°C)(100°C - 28°C)

2400t = 1360800

t = 567 s

t = 9.45 min

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .