A ball moving with an initial velocity of 100 m/s north is given an acceleration of 10 m/s2 south. What will its velocity be after 6.0 s?

Given:

initial velocity(u)=100m/s

acceleration(a)= -10m/s²(as it is in opposite direction)

time(t)=6s

To find:

final velocity(v)

Solution:

By v-u+at, we get

v=100+(-10)6

v=100-60

v=40m/s

Thus, it's velocity after 6 seconds will be 40m/s.

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