A driver loses control of a car, drives off an embankment, and lands in a canyon 6.0 m below. What was the car's speed just before touching the ground if it was traveling on the level surface at 12 m/s before the driver lost control?

Hi there!

The horizontal component of the car's velocity (12 m/s) remains CONSTANT in the absence of air resistance.

Its vertical component of its velocity is being affected by gravity. We can use the kinematic equation:

vf = final velocity (? m/s)

vi = initial velocity (0 m/s)

a = acceleration due to gravity (9.8 m/s²)

d = displacement (6m)

Plug in the given values:

The speed is derived by using the pythagorean theorem as the above are simply the COMPONENTS of the total speed.

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