an arrow is shot from a bow at an angle of 40º from the horizontal at a speed of 24.0 m/s. ignoring air resistance, what is the arrow’s maximum height above its launch point?

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

there are no components of a physical goal mentioned on the list of choices that you've provided.