A ball is launched as a projectile with initial speed v at an angle θ above the horizontal. using conservation of energy, find the maximum height hmax of the ball's flight. express your answer in terms of v, g, and θθ.

Explanation:

I will us θ as the angle above horizontal as I don't know how to make your chosen symbol for angle.

           KEy = PE

½m(vsinθ)² = mgh

                h = (vsinθ)²/2g

explanation:

could i give you a exaplo that could you?

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2