UN MÓVIL TIENE UNA VELOCIDAD INICIAL DE 30 M/SEG. COMIENZA a desacelerar a razón de 0,5 m/s2. cuánto tiempo tardó en detenerse y qué distancia recorrió.

15.3 cos 65 degrees trig

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft