Considerar tres fuerzas aplicadas al punto A de la figura, con r = 1,5 pies y: F1 = (6,0,0) lbf

F2 = (6,-7,14)

F3 = (5,0,-3)

Usando O como referencia, encontrar el momento resultante debido a estas tres fuerzas.

Hypothesis. why don’t you know this? i learned this stuff in like 5th grade

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

Answerboth technicians (a) and (b);