Physics, 03.12.2021 06:30, sreyasusanbinu

Two constant forces act on an object of mass m = 4.10 kg object moving in the xy plane as shown in the figure below. Force F with arrow1 is 24.5 N at 35.0°, and force F with arrow2 is 48.5 N at 150°. At time t = 0, the object is at the origin and has velocity (3.40î + 2.80ĵ) m/s. (a) Express the two forces in unit-vector notation.
F with arrow1 =
N
F with arrow2 =
N

(b) Find the total force exerted on the object.
N

(c) Find the object's acceleration.
m/s2

Now, consider the instant t = 3.00 s.
(d) Find the object's velocity.
m/s

(e) Find its position.
m

(f) Find its kinetic energy from ½mvf2.
kJ

(g) Find its kinetic energy from ½mvi2 + ΣF with arrow · Δvector r.
kJ

(h) What conclusion can you draw by comparing the answers to parts (f) and (g)?

Answers: 2

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Two constant forces act on an object of mass m = 4.10 kg object moving in the xy plane as shown in t...