The floor grid in Figure 1 is subject to a uniform pressure of SN/2 kPa. All dimensions are in meters. (a) Draw the tributary area of the interior beam X-Y, girder C3-D3 and column A1.
(b) Calculate and sketch the loading acting on each of the above elements.

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explanation:

wheres the pic

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j