Two tugboats are towing a large boat, of mass 15000 kg, back to shore. Tugboat 1 is pulling with a force of 8000 N at an angle of 30° north of the forward motion and tugboat 2 is pulling with a force of 9000 N at an angle θ south of the forward motion. If there is a resistive motion of 1200 N opposing the eastern motion, what is the acceleration of the large boat?

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

M= 700 kgvalue of g( gravity) is constant = 9.8 m/s² or 10 m/s² w = mg = 700*9.8 = 6860n or 6.680*10³ n