!! Apps District Bookmarks A 600 kg elevator initially moving upward undergoes motion represented by the
velocity vs time graph shown. Calculate the acceleration of the elevator. (Enter
your answer as three significant figures without units or spaces. Ex) If the
acceleration=0.59871 m/s 2 enter "0.599") *
velocity
(5/11)
7
6
5
4
3
2
1
time
(8)
0
1 2 3 4
5 6 7
Your answer

No because scientist are still changing there mines today so they are not correct to this day

From negative to negative

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.