An object is thrown vertically upward such that it has a speed 25m/s when it reaches two thirds of its maximum height above the launch point Determine this maximum height.

Explanation:

dropped from maximum height were vertical velocity is zero, the object would have a velocity of 25 m/s in a distance of

v² = u² + 2as

s = (v² - u²) / 2a

s = (25² - 0²) / (2(9.8))

s = 31.887755... m

s/h = 1 - ⅔

s/h = ⅓

h = 3s

h = 3(31.887755)

h = 95.6632...

h = 96 m

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force