A soccer ball is kicked directly up in the air. If its velocity is 5.38 m/s upward after traveling for 0.64s, A. What was its velocity when it was first kicked?
B. How long will it remain in the air for?
C. What will its be its velocity after 1 second?
D. How high will it rise?

d) physical means can be used to separate the components of air.

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft