You fire a projectile at an angle along flat ground, giving it an initial horizontal velocity of 8.43 m/s and an initial vertical
velocity of 7.07 m/s.
(the resulting initial speed is vo = 11 m/s at an angle of
00 40 degrees above the horizontal)
How long is the projectile in the air? 1
=
х
S
What is the projectile's speed as it passes through the highest
point in its trajectory? -11
x m/s

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

true is the correct answer

hope i

see earlier

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray