3. Yumyum pulls a box to the left with 300 N of force. Mamu also pulls the box to the left with 250 N of force. The box has a mass of 25 kg.
a. What is the net force acting on the box?
b. What is the box's acceleration?

The net force acting on the box is 550 N (going leftwards) and the box's acceleration is 22 meters per second squared.

Explanation:

A)

The net force acting on the box is the sum of the forces. Since Yumyum pulls with a force of 300 N and Mamu pulls with a force of 250 N, both to the left, the net force (in the x-direction) will be:

B)

The net force is equal to the object's mass multiplied by its acceleration. That is:

Substitute known values:

Find a:

In conclusion, the net force acting on the box is 550 N (going leftwards) and the box's acceleration is 22 meters per second squared.

no

explanation:

no i dont know how to solve this you should probably try to google the answer