A 250 g blob of clay moves with a speed of 15 m/s towards a 400 g cart that is initially at rest. a). What is the momentum of the system before the blob of clay strikes the cart? b). What must be the momentum of the system after they come together? ( Please note, a response of "the same " is insufficient and will result in minimal credit). c. If the blob of clay sticks to the cart, with what speed will the clay and cart move after they come together?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j