what weight of water would exert a pressure of 2000 Pascal on a base of a rectangular water tank with dimension 50 m by 20 m. what weight of water would exert a pressure of 2000 pascal's on a base of a rectangular water tank with dimension 50 m by 20 m

Pressure depends on the height of the water not on the area of the tank.

P (ressure) = density * g * h

h = 2000 nt / m^2 / (1000 kg / m^3 * 9.8 m / s^2) = .204 m

W = M V g = M h A * g

If you want the weight of the water on the entire base (A = 1000 m^2)

W = 1000 kg / m^3 * .204 m * 1000 m^2 = 2.04E5 * 9.8 m / s^2

W = 2E6  

But pressure = Force / area

Force = 2000 * 1000 = 2E6

Not sure what they are asking here

2b2t

explanation:

2b2t

see earlier