How to determine the period T with an error of T = 0.02s when using a clock with a hand given that the error when using this meter is ±0.2s

a person with a mass of 106kg has a weight of 1060n

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west