2. What is
the speed of a ball that is attached to a string and swings in a horizontal
circle of a radius 3.0 m with a centripetal acceleration of 15 m/s2?

Radius = 3 m

Centripetal acceleration = 15 m/s^2

We know, centripetal acceleration= square of Velocity/Radius

or, Square of velocity = Centripetal Acceleration× Radius

Therefore, the square of velocity

= (15 × 3) m/s = 45 m/s

Therefore, the speed

= √45 m/s

= √3×3×5 m/s

= 3√5 m/s

The answer is 3√5 m/s.

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