A grapefruit falls from a tree and hits the ground 0.64 s later. How far did the grapefruit drop?

Approximately , assuming that and that air resistance is negligible.

Explanation:

If air resistance is negligible, the acceleration of this grapefruit during the fall would be constantly equal to (gravitational field strength.)

Let denote the distance that the grapefruit travelled during the fall. The following SUVAT equation gives an expression for in terms of , , and :

.

In this question, the grapefruit was initially on a tree. Hence, assume that the initially velocity of this grapefruit was right before the fall started.

If there was no drag on the grapefruit during the fall, the acceleration of this grapefruit would be equal to the gravitational field strength: .

The duration of the fall, , has also been given. Hence, the distance that the grapefruit travelled during the fall would be:

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explanation:

area of focus