Two charges, q1 = 3 X 10^-6 C and q2 = 3 x 10°C, are connected by an insulating rod 10 m long. The rod is pivoted about its midpoint. The rod is kept horizontal 10 cm above the floor. Two identical charges, q = 5 x 10^-6 C, are fixed directly below q1 and q2, as shown Where should a 3-kg weight be placed on the rod. keep the rod horizontal? ​

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

prndulum needs thread, weight clock to time swings