Two paper screens A and B are separated by a distance of 100m. A bullet pierces A and then B such that the hole in B is 0.1m below the hole in A. If the bullet is travelling horizontally at the time of passing through A, calculate the velocity of the bullet when it hits the screen A. Neglect the resistance of the paper. Take g = 9.8m/s^2.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

b. lifting dumbbell weight at 20-degree angle from the body after a 45-degree angle