Physics, 13.09.2021 03:40, Adanysa

The ratio for the cross section areas of the tube is A2
A1
= 0.535, the difference in the
pressures is P1 − P2 = dP = 29.9 Pa , and the
density of the fluid is 2.97 kg/m3
.
Find the speed of the fluid near the right
hand end of the tube (i. e., find v2).
Answer in units of m/s.

The ratio for the cross section areas of the

tube is A2
A1
= 0.535, the difference in the
pressur

Answers: 3

Show answers

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The ratio for the cross section areas of the tube is A2
A1
= 0.535, the difference in...