A basketball is rolling rightward onto the court with a speed of 4.0\,\dfrac{\text m}{\text s}4.0 s
m
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4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction, and slows down with a constant leftward acceleration of magnitude 0.50\,\dfrac{\text m}{\text s^2}0.50
s
2

m
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0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction over 14\,\text m14m14, start text, m, end text.
What is the velocity of the basketball after rolling for 14\,\text m14m14, start text, m, end text?

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction 

The correct answer should be b let me know if i’m wrong