Extra Points because there are three questions. 1. An object goes from 20 m/s to 5 m/s in 1.2 seconds. What is the acceleration of the object?

a=vf-vi/t

2. What is the difference between distance and displacement? What is the difference between mass and weight?

3. What is the force necessary to accelerate a 40 kg object to 6 m/s/s?

F=ma

Which is a substance that can be separated by physical means and is not the same throughout

The lift raises a car of mass 850 kg to a height of 2.1 m. it uses a force of 8330 n and takes 4 seconds to raise the car. what is the power of the lift?

Now that we have a feel for the state of the circuit in its steady state, let us obtain the expression for the current in the circuit as a function of time. note that we can use the loop rule (going around counterclockwise): e−vr−vl=0. note as well that vr=ir and vl=ldidt. using these equations, we can get, after some rearranging of the variables and making the subsitution x=er−i, dxx=−rldt. integrating both sides of this equation yields x=x0e−rt/l. use this last expression to obtain an expression for i(t). remember that x=er−i and that i0=i(0)=0. express your answer in terms of e, r, and l. you may or may not need all these variables. use the notation exp(x) for ex.