Two students are on a balcony 19.6m above the street. one student throws a ball vertically downward at 14.7 m/s. At the same instant the other student throws a ball vertically upward at the same speed. the second ball just misses the balcony on the way down. a. what is the difference in the time the balls spend in the air?

b.

hope this : )

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

3. dark matter

empty space could also be a simple vacuum