A spider walks a distance of 0.2 m at a constant speed of 0.1 m/s. The time interval is A.2 s
B.0.02s
C.0.5s
D.20s

A. 2s

Explanation:

time = distance ÷ speed

T = .2 ÷.1

T= 2

answer: a. same unit

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s