A bus has velocity of 20 m/s towards east and another bus has velocity of 15 m/s in west direction . if they start to move from a point simultaneously, what distance do they cover in 2 minutes ? what will be their seperation ? Help plss!!

3.8 km

Explanation:

Eastern Side Bus

Velocity = 20m/s

Covers distance in 2 min (120sec) = 20×120 = 2400m = 2 km

Western Side Bus

Velocity = 15m/s

Covers distance in 2 min (120sec) = 15×120 = 1800m = 1.8 km

Separation Distance = 2+1.8 = 3.8 km

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft