A 350 N uniform 1.50 m bar is suspended horizontally by two vertical cables at each end. Cable A can support a max tension of 500 N without breaking and cable B can support 400 N. You want to place a small weight on this bar. What is the heaviest weight you can put on without breaking either cable?
A) 450 N
B) 500 N
C) 550 N
D) 300 N
E) 350 N
Where should you put this weight from the left end of the bar?
A) 0.40 m
B) 0.61 m
C) 0.75 m
D) 0.84 m
E) 1.0 m

The answer is -6hope this

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

This ain't even a question. speak english