A 200 g piece of ice at 0°C is placed in 500 g of water at 20°C. The system is in a container of negligible heat capacity and insulated from its surroundings. a. What is the final equilibrium temperature of the system?
b. How much of the ice melts?

Solution :

Given data :

Mass of ice, m = 200 g

Mass of water, M = 500 g

Temperature of ice = 0°C

Temperature of water = 20°C

We known ;

The latent heat of fusion of water is

The specific heat of water, C = 4.18 kJ/kg K

a). Heat required to change the ice into water is :

  J

Heat required to cool the warm water is :

From above result,

This means that total ice could not melt.

So, the temperature must be T = 0°C

b). Q' = mL

m = 0.1253 kg

m = 125.3 g

m = 125 g

Therefore, 125 g of ice had melted.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min