A proton moves perpendicular to a uniform magnetic field at a speed of 1.75 107 m/s and experiences an acceleration of 2.25 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field.

B = 0.013(-j) T

Explanation:

Given that,

The speed of a proton,

Acceleration experienced by the proton,

We need to find the magnitude and the direction of the magnetic field. At equilibrium,

The velocity is in +z direction, force in +x direction, then the field must be in -y direction.

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation:

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.