Physics, 22.07.2021 14:00, jayyd679

Con lắc lò xo thẳng đứng, vật nặng có khối lượng m = 400 g. Tại thời điểm t = 0, kéo m xuống dưới vị trí cân bằng để lò xo giãn 2,6 cm đồng thời truyền cho m vận tốc 25 cm/s hướng lên ngược chiều dương Ox, lấy
g = 10 m/s2
. Dao động với cơ năng toàn phần E = 25 mJ.
a. Viết phương trình dao động. Chọn gốc tọa độ O là vị trí cân bằng.
b. Tính thế năng đàn hồi cực đại và cực tiểu của lò xo.

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Con lắc lò xo thẳng đứng, vật nặng có khối lượng m = 400 g. Tại thời điểm t = 0, kéo m xuống dưới vị...