A 45.0 kg student runs at a constant velocity up the incline 6 metres high. If the power output of the student is 1.50 x 103 W, how long does it take the student to run the 9.0 m along the incline?

The time taken is 1.76 s.

Explanation:

mass of student, m = 45 kg

height, h = 6 m

power, P = 1500 W

Power is defined as the rate of doing work.

Work done in moving height is

W = m g h

Let the time is t.

P = m g h / t

1500 = 45 x 9.8 x 6 / t

t = 1.76 s

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