An upright image which reduced in size 10 times occurred in a mirror. If the radius of curvature of the mirror is 2 m, bow far is the object from the mirror?​

-10/9 m

Explanation:

Radius of curvature, R=2 m

Focal length of mirror, f=R/2=2/2=1 m

Let height of object=h

Height of image, h'=h-10h=-9h

We have to find the distance of object from the mirror.

Magnification, m=

Image is upright and small in size it means the mirror is convex.

Focal length of convex mirror is negative.

f=-1m

Now, mirror formula

Hence, the distance of object  from the mirror is -10/9 m

! 55 !  

write a paragraph or story to explain the transformation between potential and kinetic energy as shown in your picture or model.  

you should have at least 5 complete sentences with a main idea and supporting details.  

you must include the following words:  

potential energy

kinetic energy

mechanical energy

conservation of energy

dude, this is hard lol : ))