Three capacitors with individual capacitances of 2 μF, 5 μF, and 10 μF respectively are connected in series with a 12V battery. What are the total

capacitance and total charge in the network?​

1.25C

Explanation:

When capacitance is in series we add them like this: 1/Ctotal = 1/C1 +1/C2 + 1/C3

1/C = 1/2 + 1/5 + 1/10 = 5 + 2 + 1/10 = 8/10

C = 10/8 = 1.25

Capacitance = Charge/potential difference(Q/V)

1.25 = Charge/12

Total charge = 1.25 ×12 =15coulombs

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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