In uplifting 750 newton load with the help of 2 meter long lever lever took 250 newton efforts . What will be the efficiency of a machine if the fulcrum is kept 50 cm from the load

the efficiency of the machine is 100%

Explanation:

Given;

load, L = 750 N

length of the lever, L = 2 m

effort applied, E = 250 N

Position of the load from the fulcrum,  = 50 cm

                                     50cm

     0↓Δ↓200 cm

    750 N                                       x cm                 250 N

Apply the principle of moment;

750(50) = 250(x)

x = (750 x 50) / (250)

x = 150 cm

the distance of the effort = 150 cm = 1.5 m

the distance of the load = 50 cm = 0.5 m

The velocity ratio of the machine = 1.5/0.5

                                                        = 3

The mechanical advantage of the machine is calculated as;

M.A = Load/effort

M.A = 750 / 250

M.A = 3

The efficiency of the machine is calculated as;

E = (M.A / V.R) x 100%

E = (3/3) x 100% = 100%

Therefore, the efficiency of the machine is 100%

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0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr