How much current flows in the circuit if two resistors of 6 connected in parallel are supplied with potential difference of 12 volts?​

4 A

Explanation:

Firstly we need to calculate the equivalent resistance. Since, two resistors of 6 connected in parallel, so equivalent resistance will be given by,

1/R = 1/R1 + 1/R2

1/R = (1/6 + 1/6) Ω

1/R = (1 + 1)/6 Ω

1/R = 2/6 Ω

R = 6/2 Ω

R = 3 Ω

We know that,

V = IR

12 = I × 3

12 ÷ 3 = I

4 Ampere = I

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hope this !

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