A baseball of mass 0.145 kg is thrown at a speed of 40.0 m/s. The batter strikes the ball with a force of 15,000 N; the bat and ball are in contact for 0.500 ms. The force is exactly opposite to the original direction of the ball. Determine the final speed of the ball.

11.7 m/s

Explanation:

An impulse results in a change of momentum

FΔt = mΔv

Δv = FΔt/m

vf - vi = FΔt/m

vf = vi + FΔt/m

Assuming the original velocity has the positive direction

vf = 40.0 + (-15000)(0.0005)/0.145

vf = -11.7241

|vf| = 11.7 m/s

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

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