how will you arrange 3 capacitors each having the capacity of 2uf, to get a capacitor of capacity 3uf?​

We arrange one of the 2μF capacitors in parallel to the other two capacitors which will be arranged in series

Explanation:

The number of capacitors in the network = 3

The capacitance of the each capacitor, C₁, C₂, and C₃ = 2 μF

The sum of capacitors in series = The inverse of the sum of the reciprocals of the capacitances of the capacitor

The sum of capacitances of capacitors arranged in parallel = The sum of the individual capacitances in parallel

= Cₐ + C

By placing two of the capacitors in series, and the third in parallel to the first two, we get;

= + C₃

∴ = 1 μF + 2μF= 3 μF

Therefore, to get a capacitor of capacity of 3 μF from 3 capacitors of

2 μF, one of the capacitors is arranged in parallel across the other two capacitors arranged in series.

1/0.14nm = 10^10/1.4 a lot

be subject to a force andchange its motion