If the distance between a neutral atom and a point charge is increased by a factor of six, by what factor does the force on the atom by the point charge change

Force will increase

Explanation:

F new/ f old = r^2/(r+6)^2=value

A neutral atom has no net charge and should not be affected by a point charge, and the distance of separation is not a factor.

if you answer my question i will answer yours

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.