A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals during the time the flashlight is in operation, how long was the flashlight used?

2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI Equation 1

Where P = Power, V = Voltage, I = Current.

make I the subject of the equation

I = P/V Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

Substitute these value into equation 4

t =  7.899×10⁻¹⁹/0.276

t = 2.86×10⁻¹⁸ seconds

chemical properties of thing